After searching the forum for my questions, I decided to share my interrogations about the charging mode of the open inverter.
(First, let's say I'm talking about "boost" mode, since most rectified domestic AC voltage will end up below most modern commercial EV pack voltage of 350-420VDC)
If one brave fellow had a good inverter hardware (think about something in the range of power of most modern EVs, 80kW to 160kW peak), with a working V2 or V3 control board, coupled with a correctly setup motor of the same power, appropriate cooling, cabling size, etc... A viable configuration.
Q: What would be the theoritical limiting factor of maximum charging power in boost mode with such a setup?
Let's not discuss about if it's right or wrong to do that and create a large non-isolated charger, nor discuss if there is sufficient power available on a single phase of 230-240VAC at home to feed this theoritical charging setup. I know that it is safer, perfectly-isolated, less noisy, more EMI/EMC friendly and more proven design to simply use an OEM or an aftermarket onboard chargers; my question is simply about the science of it all on the open inverter hardware: using the inverter+motor combo as a powerful charger.
For conversation sake, let's suppose :
- there is an infinity of AC power available on that 230VAC phase,
- there is a perfectly sized isolation transformer present in the room to keep it all nice and isolated,
- there is also a GFCI in this circuit,
- there is an isolation monitoring device in the vehicle ensuring DC-link is 1-2megaohm from chassis/earth,
- there is plenty of cooling for the inverter&motor
- this is all happening in a faraday-garage

I know in boost mode, only one of the three IGBT pairs is used, so the limit would probably come from there, but the official wiki page explaining charging mode is stating "At least for lower power charging (say below 5kW)". Where is that limit coming from? What prevents a good motor-inverter combo (capable of delivering a 50-60kW for many minutes) from delivering 15-20kW of charging power (one third of its limit)?
Thanks for enlightening me.